4(n-2)=3(n-5)

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Solution for 4(n-2)=3(n-5) equation:



4(n-2)=3(n-5)
We move all terms to the left:
4(n-2)-(3(n-5))=0
We multiply parentheses
4n-(3(n-5))-8=0
We calculate terms in parentheses: -(3(n-5)), so:
3(n-5)
We multiply parentheses
3n-15
Back to the equation:
-(3n-15)
We get rid of parentheses
4n-3n+15-8=0
We add all the numbers together, and all the variables
n+7=0
We move all terms containing n to the left, all other terms to the right
n=-7

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