4(n-2)=3(n-5)

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Solution for 4(n-2)=3(n-5) equation: 



4(n-2)=3(n-5)

We move all terms to the left:

4(n-2)-(3(n-5))=0

We multiply parentheses

4n-(3(n-5))-8=0



We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)



We get rid of parentheses

4n-3n+15-8=0

We add all the numbers together, and all the variables

n+7=0

We move all terms containing n to the left, all other terms to the right

n=-7

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