4(n-2/n)

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Solution for 4(n-2/n) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4*(n-(2/n)) = 0

4*(n-2*n^-1) = 0

n-2*n^-1 = 0

n^-1*(n^2-2) = 0

1*n^2 = 2 // : 1

n^2 = 2

n^2 = 2 // ^ 1/2

abs(n) = 2^(1/2)

n = 2^(1/2) or n = -2^(1/2)

n^-1*(n-2^(1/2))*(n+2^(1/2)) = 0

4*n^-1*(n-2^(1/2))*(n+2^(1/2)) = 0

( n+2^(1/2) )

n+2^(1/2) = 0 // - 2^(1/2)

n = -2^(1/2)

( n-2^(1/2) )

n-2^(1/2) = 0 // + 2^(1/2)

n = 2^(1/2)

( n^-1 )

1*n^-1 = 0 // : 1

n^-1 = 0

n naleu017Cy do O

n in { -2^(1/2), 2^(1/2) }

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