4(n-3)+2n=6n-6(8-n)

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Solution for 4(n-3)+2n=6n-6(8-n) equation: 



4(n-3)+2n=6n-6(8-n)

We move all terms to the left:

4(n-3)+2n-(6n-6(8-n))=0

We add all the numbers together, and all the variables

4(n-3)+2n-(6n-6(-1n+8))=0

We add all the numbers together, and all the variables

2n+4(n-3)-(6n-6(-1n+8))=0

We multiply parentheses

2n+4n-(6n-6(-1n+8))-12=0



We calculate terms in parentheses: -(6n-6(-1n+8)), so:

6n-6(-1n+8)

We multiply parentheses

6n+6n-48

We add all the numbers together, and all the variables

12n-48

Back to the equation:

-(12n-48)



We add all the numbers together, and all the variables

6n-(12n-48)-12=0

We get rid of parentheses

6n-12n+48-12=0

We add all the numbers together, and all the variables

-6n+36=0

We move all terms containing n to the left, all other terms to the right

-6n=-36

n=-36/-6

n=+6

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