4(n-3)+8(y-2)=

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Solution for 4(n-3)+8(y-2)= equation:


Simplifying
4(n + -3) + 8(y + -2) = 0

Reorder the terms:
4(-3 + n) + 8(y + -2) = 0
(-3 * 4 + n * 4) + 8(y + -2) = 0
(-12 + 4n) + 8(y + -2) = 0

Reorder the terms:
-12 + 4n + 8(-2 + y) = 0
-12 + 4n + (-2 * 8 + y * 8) = 0
-12 + 4n + (-16 + 8y) = 0

Reorder the terms:
-12 + -16 + 4n + 8y = 0

Combine like terms: -12 + -16 = -28
-28 + 4n + 8y = 0

Solving
-28 + 4n + 8y = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 4n + 28 + 8y = 0 + 28

Reorder the terms:
-28 + 28 + 4n + 8y = 0 + 28

Combine like terms: -28 + 28 = 0
0 + 4n + 8y = 0 + 28
4n + 8y = 0 + 28

Combine like terms: 0 + 28 = 28
4n + 8y = 28

Add '-8y' to each side of the equation.
4n + 8y + -8y = 28 + -8y

Combine like terms: 8y + -8y = 0
4n + 0 = 28 + -8y
4n = 28 + -8y

Divide each side by '4'.
n = 7 + -2y

Simplifying
n = 7 + -2y

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