4(n-3)=-20

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Solution for 4(n-3)=-20 equation: 



4(n-3)=-20

We move all terms to the left:

4(n-3)-(-20)=0

We add all the numbers together, and all the variables

4(n-3)+20=0

We multiply parentheses

4n-12+20=0

We add all the numbers together, and all the variables

4n+8=0

We move all terms containing n to the left, all other terms to the right

4n=-8

n=-8/4

n=-2

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