4(n-3)=14-2(n+1)

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Solution for 4(n-3)=14-2(n+1) equation:


Simplifying
4(n + -3) = 14 + -2(n + 1)

Reorder the terms:
4(-3 + n) = 14 + -2(n + 1)
(-3 * 4 + n * 4) = 14 + -2(n + 1)
(-12 + 4n) = 14 + -2(n + 1)

Reorder the terms:
-12 + 4n = 14 + -2(1 + n)
-12 + 4n = 14 + (1 * -2 + n * -2)
-12 + 4n = 14 + (-2 + -2n)

Combine like terms: 14 + -2 = 12
-12 + 4n = 12 + -2n

Solving
-12 + 4n = 12 + -2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '2n' to each side of the equation.
-12 + 4n + 2n = 12 + -2n + 2n

Combine like terms: 4n + 2n = 6n
-12 + 6n = 12 + -2n + 2n

Combine like terms: -2n + 2n = 0
-12 + 6n = 12 + 0
-12 + 6n = 12

Add '12' to each side of the equation.
-12 + 12 + 6n = 12 + 12

Combine like terms: -12 + 12 = 0
0 + 6n = 12 + 12
6n = 12 + 12

Combine like terms: 12 + 12 = 24
6n = 24

Divide each side by '6'.
n = 4

Simplifying
n = 4

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