4(n-3)=3(n+1)

Solution for 4(n-3)=3(n+1) equation:

Simplifying
4(n + -3) = 3(n + 1)

Reorder the terms:
4(-3 + n) = 3(n + 1)
(-3 * 4 + n * 4) = 3(n + 1)
(-12 + 4n) = 3(n + 1)

Reorder the terms:
-12 + 4n = 3(1 + n)
-12 + 4n = (1 * 3 + n * 3)
-12 + 4n = (3 + 3n)

Solving
-12 + 4n = 3 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-12 + 4n + -3n = 3 + 3n + -3n

Combine like terms: 4n + -3n = 1n
-12 + 1n = 3 + 3n + -3n

Combine like terms: 3n + -3n = 0
-12 + 1n = 3 + 0
-12 + 1n = 3

Add '12' to each side of the equation.
-12 + 12 + 1n = 3 + 12

Combine like terms: -12 + 12 = 0
0 + 1n = 3 + 12
1n = 3 + 12

Combine like terms: 3 + 12 = 15
1n = 15

Divide each side by '1'.
n = 15

Simplifying
n = 15