4(n-3)=3+4n+3n

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Solution for 4(n-3)=3+4n+3n equation: 



4(n-3)=3+4n+3n

We move all terms to the left:

4(n-3)-(3+4n+3n)=0

We add all the numbers together, and all the variables

4(n-3)-(7n+3)=0

We multiply parentheses

4n-(7n+3)-12=0

We get rid of parentheses

4n-7n-3-12=0

We add all the numbers together, and all the variables

-3n-15=0

We move all terms containing n to the left, all other terms to the right

-3n=15

n=15/-3

n=-5

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