4(n-3)=n-2(12-3n)

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Solution for 4(n-3)=n-2(12-3n) equation: 



4(n-3)=n-2(12-3n)

We move all terms to the left:

4(n-3)-(n-2(12-3n))=0

We add all the numbers together, and all the variables

4(n-3)-(n-2(-3n+12))=0

We multiply parentheses

4n-(n-2(-3n+12))-12=0



We calculate terms in parentheses: -(n-2(-3n+12)), so:

n-2(-3n+12)

We multiply parentheses

n+6n-24

We add all the numbers together, and all the variables

7n-24

Back to the equation:

-(7n-24)



We get rid of parentheses

4n-7n+24-12=0

We add all the numbers together, and all the variables

-3n+12=0

We move all terms containing n to the left, all other terms to the right

-3n=-12

n=-12/-3

n=+4

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