4(n-3)=n-2(12-3n)

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Solution for 4(n-3)=n-2(12-3n) equation:



4(n-3)=n-2(12-3n)
We move all terms to the left:
4(n-3)-(n-2(12-3n))=0
We add all the numbers together, and all the variables
4(n-3)-(n-2(-3n+12))=0
We multiply parentheses
4n-(n-2(-3n+12))-12=0
We calculate terms in parentheses: -(n-2(-3n+12)), so:
n-2(-3n+12)
We multiply parentheses
n+6n-24
We add all the numbers together, and all the variables
7n-24
Back to the equation:
-(7n-24)
We get rid of parentheses
4n-7n+24-12=0
We add all the numbers together, and all the variables
-3n+12=0
We move all terms containing n to the left, all other terms to the right
-3n=-12
n=-12/-3
n=+4

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