4(n-4)+2=3(n+8)

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Solution for 4(n-4)+2=3(n+8) equation: 



4(n-4)+2=3(n+8)

We move all terms to the left:

4(n-4)+2-(3(n+8))=0

We multiply parentheses

4n-(3(n+8))-16+2=0



We calculate terms in parentheses: -(3(n+8)), so:

3(n+8)

We multiply parentheses

3n+24

Back to the equation:

-(3n+24)



We add all the numbers together, and all the variables

4n-(3n+24)-14=0

We get rid of parentheses

4n-3n-24-14=0

We add all the numbers together, and all the variables

n-38=0

We move all terms containing n to the left, all other terms to the right

n=38

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