4(n-4)=32

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Solution for 4(n-4)=32 equation: 



4(n-4)=32

We move all terms to the left:

4(n-4)-(32)=0

We multiply parentheses

4n-16-32=0

We add all the numbers together, and all the variables

4n-48=0

We move all terms containing n to the left, all other terms to the right

4n=48

n=48/4

n=12

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