4(n-5)=-36+2n

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Solution for 4(n-5)=-36+2n equation: 



4(n-5)=-36+2n

We move all terms to the left:

4(n-5)-(-36+2n)=0

We add all the numbers together, and all the variables

4(n-5)-(2n-36)=0

We multiply parentheses

4n-(2n-36)-20=0

We get rid of parentheses

4n-2n+36-20=0

We add all the numbers together, and all the variables

2n+16=0

We move all terms containing n to the left, all other terms to the right

2n=-16

n=-16/2

n=-8

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