4(n-7)-2(n+3)=y-1

Solution for 4(n-7)-2(n+3)=y-1 equation:

Simplifying
4(n + -7) + -2(n + 3) = y + -1

Reorder the terms:
4(-7 + n) + -2(n + 3) = y + -1
(-7 * 4 + n * 4) + -2(n + 3) = y + -1
(-28 + 4n) + -2(n + 3) = y + -1

Reorder the terms:
-28 + 4n + -2(3 + n) = y + -1
-28 + 4n + (3 * -2 + n * -2) = y + -1
-28 + 4n + (-6 + -2n) = y + -1

Reorder the terms:
-28 + -6 + 4n + -2n = y + -1

Combine like terms: -28 + -6 = -34
-34 + 4n + -2n = y + -1

Combine like terms: 4n + -2n = 2n
-34 + 2n = y + -1

Reorder the terms:
-34 + 2n = -1 + y

Solving
-34 + 2n = -1 + y

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '34' to each side of the equation.
-34 + 34 + 2n = -1 + 34 + y

Combine like terms: -34 + 34 = 0
0 + 2n = -1 + 34 + y
2n = -1 + 34 + y

Combine like terms: -1 + 34 = 33
2n = 33 + y

Divide each side by '2'.
n = 16.5 + 0.5y

Simplifying
n = 16.5 + 0.5y