4(n-8)+2(n+4)=36

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Solution for 4(n-8)+2(n+4)=36 equation: 



4(n-8)+2(n+4)=36

We move all terms to the left:

4(n-8)+2(n+4)-(36)=0

We multiply parentheses

4n+2n-32+8-36=0

We add all the numbers together, and all the variables

6n-60=0

We move all terms containing n to the left, all other terms to the right

6n=60

n=60/6

n=10

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