4(n=1)+2n+3=55

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Solution for 4(n=1)+2n+3=55 equation: 



4(n=1)+2n+3=55

We move all terms to the left:

4(n-(1)+2n+3)=0

We add all the numbers together, and all the variables

4(3n+2)=0

We multiply parentheses

12n+8=0

We move all terms containing n to the left, all other terms to the right

12n=-8

n=-8/12

n=-2/3

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