4(p+3)=3(p-2)+p+18

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Solution for 4(p+3)=3(p-2)+p+18 equation:


Simplifying
4(p + 3) = 3(p + -2) + p + 18

Reorder the terms:
4(3 + p) = 3(p + -2) + p + 18
(3 * 4 + p * 4) = 3(p + -2) + p + 18
(12 + 4p) = 3(p + -2) + p + 18

Reorder the terms:
12 + 4p = 3(-2 + p) + p + 18
12 + 4p = (-2 * 3 + p * 3) + p + 18
12 + 4p = (-6 + 3p) + p + 18

Reorder the terms:
12 + 4p = -6 + 18 + 3p + p

Combine like terms: -6 + 18 = 12
12 + 4p = 12 + 3p + p

Combine like terms: 3p + p = 4p
12 + 4p = 12 + 4p

Add '-12' to each side of the equation.
12 + -12 + 4p = 12 + -12 + 4p

Combine like terms: 12 + -12 = 0
0 + 4p = 12 + -12 + 4p
4p = 12 + -12 + 4p

Combine like terms: 12 + -12 = 0
4p = 0 + 4p
4p = 4p

Add '-4p' to each side of the equation.
4p + -4p = 4p + -4p

Combine like terms: 4p + -4p = 0
0 = 4p + -4p

Combine like terms: 4p + -4p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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