4(p-6)+6=120-10

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Solution for 4(p-6)+6=120-10 equation: 



4(p-6)+6=120-10

We move all terms to the left:

4(p-6)+6-(120-10)=0

We add all the numbers together, and all the variables

4(p-6)+6-110=0

We add all the numbers together, and all the variables

4(p-6)-104=0

We multiply parentheses

4p-24-104=0

We add all the numbers together, and all the variables

4p-128=0

We move all terms containing p to the left, all other terms to the right

4p=128

p=128/4

p=32

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