4(q+2)+3q=-20

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Solution for 4(q+2)+3q=-20 equation: 



4(q+2)+3q=-20

We move all terms to the left:

4(q+2)+3q-(-20)=0

We add all the numbers together, and all the variables

3q+4(q+2)+20=0

We multiply parentheses

3q+4q+8+20=0

We add all the numbers together, and all the variables

7q+28=0

We move all terms containing q to the left, all other terms to the right

7q=-28

q=-28/7

q=-4

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