4(q+4)=28

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Solution for 4(q+4)=28 equation: 



4(q+4)=28

We move all terms to the left:

4(q+4)-(28)=0

We multiply parentheses

4q+16-28=0

We add all the numbers together, and all the variables

4q-12=0

We move all terms containing q to the left, all other terms to the right

4q=12

q=12/4

q=3

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