4(q+5)=2q+28

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Solution for 4(q+5)=2q+28 equation: 



4(q+5)=2q+28

We move all terms to the left:

4(q+5)-(2q+28)=0

We multiply parentheses

4q-(2q+28)+20=0

We get rid of parentheses

4q-2q-28+20=0

We add all the numbers together, and all the variables

2q-8=0

We move all terms containing q to the left, all other terms to the right

2q=8

q=8/2

q=4

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