4(q-1)-6q=3(2-q)-127

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Solution for 4(q-1)-6q=3(2-q)-127 equation: 



4(q-1)-6q=3(2-q)-127

We move all terms to the left:

4(q-1)-6q-(3(2-q)-127)=0

We add all the numbers together, and all the variables

4(q-1)-6q-(3(-1q+2)-127)=0

We add all the numbers together, and all the variables

-6q+4(q-1)-(3(-1q+2)-127)=0

We multiply parentheses

-6q+4q-(3(-1q+2)-127)-4=0



We calculate terms in parentheses: -(3(-1q+2)-127), so:

3(-1q+2)-127

We multiply parentheses

-3q+6-127

We add all the numbers together, and all the variables

-3q-121

Back to the equation:

-(-3q-121)



We add all the numbers together, and all the variables

-2q-(-3q-121)-4=0

We get rid of parentheses

-2q+3q+121-4=0

We add all the numbers together, and all the variables

q+117=0

We move all terms containing q to the left, all other terms to the right

q=-117

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