4(q-3)+6=3(q+10)-q

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Solution for 4(q-3)+6=3(q+10)-q equation: 



4(q-3)+6=3(q+10)-q

We move all terms to the left:

4(q-3)+6-(3(q+10)-q)=0

We multiply parentheses

4q-(3(q+10)-q)-12+6=0



We calculate terms in parentheses: -(3(q+10)-q), so:

3(q+10)-q

We add all the numbers together, and all the variables

-1q+3(q+10)

We multiply parentheses

-1q+3q+30

We add all the numbers together, and all the variables

2q+30

Back to the equation:

-(2q+30)



We add all the numbers together, and all the variables

4q-(2q+30)-6=0

We get rid of parentheses

4q-2q-30-6=0

We add all the numbers together, and all the variables

2q-36=0

We move all terms containing q to the left, all other terms to the right

2q=36

q=36/2

q=18

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