4(q-4)=7q+5

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Solution for 4(q-4)=7q+5 equation: 



4(q-4)=7q+5

We move all terms to the left:

4(q-4)-(7q+5)=0

We multiply parentheses

4q-(7q+5)-16=0

We get rid of parentheses

4q-7q-5-16=0

We add all the numbers together, and all the variables

-3q-21=0

We move all terms containing q to the left, all other terms to the right

-3q=21

q=21/-3

q=-7

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