4(q-8)+q-3=5(q-7)

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Solution for 4(q-8)+q-3=5(q-7) equation:


Simplifying
4(q + -8) + q + -3 = 5(q + -7)

Reorder the terms:
4(-8 + q) + q + -3 = 5(q + -7)
(-8 * 4 + q * 4) + q + -3 = 5(q + -7)
(-32 + 4q) + q + -3 = 5(q + -7)

Reorder the terms:
-32 + -3 + 4q + q = 5(q + -7)

Combine like terms: -32 + -3 = -35
-35 + 4q + q = 5(q + -7)

Combine like terms: 4q + q = 5q
-35 + 5q = 5(q + -7)

Reorder the terms:
-35 + 5q = 5(-7 + q)
-35 + 5q = (-7 * 5 + q * 5)
-35 + 5q = (-35 + 5q)

Add '35' to each side of the equation.
-35 + 35 + 5q = -35 + 35 + 5q

Combine like terms: -35 + 35 = 0
0 + 5q = -35 + 35 + 5q
5q = -35 + 35 + 5q

Combine like terms: -35 + 35 = 0
5q = 0 + 5q
5q = 5q

Add '-5q' to each side of the equation.
5q + -5q = 5q + -5q

Combine like terms: 5q + -5q = 0
0 = 5q + -5q

Combine like terms: 5q + -5q = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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