4(q-8)=7q+8

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Solution for 4(q-8)=7q+8 equation: 



4(q-8)=7q+8

We move all terms to the left:

4(q-8)-(7q+8)=0

We multiply parentheses

4q-(7q+8)-32=0

We get rid of parentheses

4q-7q-8-32=0

We add all the numbers together, and all the variables

-3q-40=0

We move all terms containing q to the left, all other terms to the right

-3q=40

q=40/-3

q=-13+1/3

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