4(q-8)=7q-5

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Solution for 4(q-8)=7q-5 equation: 



4(q-8)=7q-5

We move all terms to the left:

4(q-8)-(7q-5)=0

We multiply parentheses

4q-(7q-5)-32=0

We get rid of parentheses

4q-7q+5-32=0

We add all the numbers together, and all the variables

-3q-27=0

We move all terms containing q to the left, all other terms to the right

-3q=27

q=27/-3

q=-9

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