4(r+1)+3=19

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Solution for 4(r+1)+3=19 equation:



4(r+1)+3=19
We move all terms to the left:
4(r+1)+3-(19)=0
We add all the numbers together, and all the variables
4(r+1)-16=0
We multiply parentheses
4r+4-16=0
We add all the numbers together, and all the variables
4r-12=0
We move all terms containing r to the left, all other terms to the right
4r=12
r=12/4
r=3

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