4(r+1)+3=19

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Solution for 4(r+1)+3=19 equation: 



4(r+1)+3=19

We move all terms to the left:

4(r+1)+3-(19)=0

We add all the numbers together, and all the variables

4(r+1)-16=0

We multiply parentheses

4r+4-16=0

We add all the numbers together, and all the variables

4r-12=0

We move all terms containing r to the left, all other terms to the right

4r=12

r=12/4

r=3

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