4(r+2)-3=10r-7-6r+12

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Solution for 4(r+2)-3=10r-7-6r+12 equation: 


Simplifying
4(r + 2) + -3 = 10r + -7 + -6r + 12

Reorder the terms:
4(2 + r) + -3 = 10r + -7 + -6r + 12
(2 * 4 + r * 4) + -3 = 10r + -7 + -6r + 12
(8 + 4r) + -3 = 10r + -7 + -6r + 12

Reorder the terms:
8 + -3 + 4r = 10r + -7 + -6r + 12

Combine like terms: 8 + -3 = 5
5 + 4r = 10r + -7 + -6r + 12

Reorder the terms:
5 + 4r = -7 + 12 + 10r + -6r

Combine like terms: -7 + 12 = 5
5 + 4r = 5 + 10r + -6r

Combine like terms: 10r + -6r = 4r
5 + 4r = 5 + 4r

Add '-5' to each side of the equation.
5 + -5 + 4r = 5 + -5 + 4r

Combine like terms: 5 + -5 = 0
0 + 4r = 5 + -5 + 4r
4r = 5 + -5 + 4r

Combine like terms: 5 + -5 = 0
4r = 0 + 4r
4r = 4r

Add '-4r' to each side of the equation.
4r + -4r = 4r + -4r

Combine like terms: 4r + -4r = 0
0 = 4r + -4r

Combine like terms: 4r + -4r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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