4(r+2)=1/5(20r+400)

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Solution for 4(r+2)=1/5(20r+400) equation: 



4(r+2)=1/5(20r+400)

We move all terms to the left:

4(r+2)-(1/5(20r+400))=0



Domain of the equation: 5(20r+400))!=0

r∈R



We multiply parentheses

4r-(1/5(20r+400))+8=0

We multiply all the terms by the denominator


4r*5(20r+400))-(1+8*5(20r+400))=0

Wy multiply elements

20r^2(2+40r(2=0

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