4(r+2)=4(2-2r)

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Solution for 4(r+2)=4(2-2r) equation: 



4(r+2)=4(2-2r)

We move all terms to the left:

4(r+2)-(4(2-2r))=0

We add all the numbers together, and all the variables

4(r+2)-(4(-2r+2))=0

We multiply parentheses

4r-(4(-2r+2))+8=0



We calculate terms in parentheses: -(4(-2r+2)), so:

4(-2r+2)

We multiply parentheses

-8r+8

Back to the equation:

-(-8r+8)



We get rid of parentheses

4r+8r-8+8=0

We add all the numbers together, and all the variables

12r=0

r=0/12

r=0

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