4(r+3)+2r=24+2r

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Solution for 4(r+3)+2r=24+2r equation: 



4(r+3)+2r=24+2r

We move all terms to the left:

4(r+3)+2r-(24+2r)=0

We add all the numbers together, and all the variables

4(r+3)+2r-(2r+24)=0

We add all the numbers together, and all the variables

2r+4(r+3)-(2r+24)=0

We multiply parentheses

2r+4r-(2r+24)+12=0

We get rid of parentheses

2r+4r-2r-24+12=0

We add all the numbers together, and all the variables

4r-12=0

We move all terms containing r to the left, all other terms to the right

4r=12

r=12/4

r=3

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