4(r+3)-2r=2r+12

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Solution for 4(r+3)-2r=2r+12 equation: 


Simplifying
4(r + 3) + -2r = 2r + 12

Reorder the terms:
4(3 + r) + -2r = 2r + 12
(3 * 4 + r * 4) + -2r = 2r + 12
(12 + 4r) + -2r = 2r + 12

Combine like terms: 4r + -2r = 2r
12 + 2r = 2r + 12

Reorder the terms:
12 + 2r = 12 + 2r

Add '-12' to each side of the equation.
12 + -12 + 2r = 12 + -12 + 2r

Combine like terms: 12 + -12 = 0
0 + 2r = 12 + -12 + 2r
2r = 12 + -12 + 2r

Combine like terms: 12 + -12 = 0
2r = 0 + 2r
2r = 2r

Add '-2r' to each side of the equation.
2r + -2r = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 2r + -2r

Combine like terms: 2r + -2r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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