4(r+3)-2r=3(r-3)

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Solution for 4(r+3)-2r=3(r-3) equation:


Simplifying
4(r + 3) + -2r = 3(r + -3)

Reorder the terms:
4(3 + r) + -2r = 3(r + -3)
(3 * 4 + r * 4) + -2r = 3(r + -3)
(12 + 4r) + -2r = 3(r + -3)

Combine like terms: 4r + -2r = 2r
12 + 2r = 3(r + -3)

Reorder the terms:
12 + 2r = 3(-3 + r)
12 + 2r = (-3 * 3 + r * 3)
12 + 2r = (-9 + 3r)

Solving
12 + 2r = -9 + 3r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-3r' to each side of the equation.
12 + 2r + -3r = -9 + 3r + -3r

Combine like terms: 2r + -3r = -1r
12 + -1r = -9 + 3r + -3r

Combine like terms: 3r + -3r = 0
12 + -1r = -9 + 0
12 + -1r = -9

Add '-12' to each side of the equation.
12 + -12 + -1r = -9 + -12

Combine like terms: 12 + -12 = 0
0 + -1r = -9 + -12
-1r = -9 + -12

Combine like terms: -9 + -12 = -21
-1r = -21

Divide each side by '-1'.
r = 21

Simplifying
r = 21

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