4(r+3)-3z=

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Solution for 4(r+3)-3z= equation:


Simplifying
4(r + 3) + -3z = 0

Reorder the terms:
4(3 + r) + -3z = 0
(3 * 4 + r * 4) + -3z = 0
(12 + 4r) + -3z = 0

Solving
12 + 4r + -3z = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + 4r + -12 + -3z = 0 + -12

Reorder the terms:
12 + -12 + 4r + -3z = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 4r + -3z = 0 + -12
4r + -3z = 0 + -12

Combine like terms: 0 + -12 = -12
4r + -3z = -12

Add '3z' to each side of the equation.
4r + -3z + 3z = -12 + 3z

Combine like terms: -3z + 3z = 0
4r + 0 = -12 + 3z
4r = -12 + 3z

Divide each side by '4'.
r = -3 + 0.75z

Simplifying
r = -3 + 0.75z

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