4(r+3)=2(r+1)

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Solution for 4(r+3)=2(r+1) equation: 



4(r+3)=2(r+1)

We move all terms to the left:

4(r+3)-(2(r+1))=0

We multiply parentheses

4r-(2(r+1))+12=0



We calculate terms in parentheses: -(2(r+1)), so:

2(r+1)

We multiply parentheses

2r+2

Back to the equation:

-(2r+2)



We get rid of parentheses

4r-2r-2+12=0

We add all the numbers together, and all the variables

2r+10=0

We move all terms containing r to the left, all other terms to the right

2r=-10

r=-10/2

r=-5

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