4(r+3)=5(r-1)

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Solution for 4(r+3)=5(r-1) equation:



4(r+3)=5(r-1)
We move all terms to the left:
4(r+3)-(5(r-1))=0
We multiply parentheses
4r-(5(r-1))+12=0
We calculate terms in parentheses: -(5(r-1)), so:
5(r-1)
We multiply parentheses
5r-5
Back to the equation:
-(5r-5)
We get rid of parentheses
4r-5r+5+12=0
We add all the numbers together, and all the variables
-1r+17=0
We move all terms containing r to the left, all other terms to the right
-r=-17
r=-17/-1
r=+17

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