4(r+3)=7-4(2r+5)

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Solution for 4(r+3)=7-4(2r+5) equation:


Simplifying
4(r + 3) = 7 + -4(2r + 5)

Reorder the terms:
4(3 + r) = 7 + -4(2r + 5)
(3 * 4 + r * 4) = 7 + -4(2r + 5)
(12 + 4r) = 7 + -4(2r + 5)

Reorder the terms:
12 + 4r = 7 + -4(5 + 2r)
12 + 4r = 7 + (5 * -4 + 2r * -4)
12 + 4r = 7 + (-20 + -8r)

Combine like terms: 7 + -20 = -13
12 + 4r = -13 + -8r

Solving
12 + 4r = -13 + -8r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '8r' to each side of the equation.
12 + 4r + 8r = -13 + -8r + 8r

Combine like terms: 4r + 8r = 12r
12 + 12r = -13 + -8r + 8r

Combine like terms: -8r + 8r = 0
12 + 12r = -13 + 0
12 + 12r = -13

Add '-12' to each side of the equation.
12 + -12 + 12r = -13 + -12

Combine like terms: 12 + -12 = 0
0 + 12r = -13 + -12
12r = -13 + -12

Combine like terms: -13 + -12 = -25
12r = -25

Divide each side by '12'.
r = -2.083333333

Simplifying
r = -2.083333333

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