4(r+4)/3=2r+7

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Solution for 4(r+4)/3=2r+7 equation:



4(r+4)/3=2r+7
We move all terms to the left:
4(r+4)/3-(2r+7)=0
We get rid of parentheses
4(r+4)/3-2r-7=0
We multiply all the terms by the denominator
4(r+4)-2r*3-7*3=0
We add all the numbers together, and all the variables
4(r+4)-2r*3-21=0
We multiply parentheses
4r-2r*3+16-21=0
Wy multiply elements
4r-6r+16-21=0
We add all the numbers together, and all the variables
-2r-5=0
We move all terms containing r to the left, all other terms to the right
-2r=5
r=5/-2
r=-2+1/2

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