4(r+9)-8=2(r-1)+36

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Solution for 4(r+9)-8=2(r-1)+36 equation: 



4(r+9)-8=2(r-1)+36

We move all terms to the left:

4(r+9)-8-(2(r-1)+36)=0

We multiply parentheses

4r-(2(r-1)+36)+36-8=0



We calculate terms in parentheses: -(2(r-1)+36), so:

2(r-1)+36

We multiply parentheses

2r-2+36

We add all the numbers together, and all the variables

2r+34

Back to the equation:

-(2r+34)



We add all the numbers together, and all the variables

4r-(2r+34)+28=0

We get rid of parentheses

4r-2r-34+28=0

We add all the numbers together, and all the variables

2r-6=0

We move all terms containing r to the left, all other terms to the right

2r=6

r=6/2

r=3

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