4(r-1)+2(r+3)=6

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Solution for 4(r-1)+2(r+3)=6 equation:


Simplifying
4(r + -1) + 2(r + 3) = 6

Reorder the terms:
4(-1 + r) + 2(r + 3) = 6
(-1 * 4 + r * 4) + 2(r + 3) = 6
(-4 + 4r) + 2(r + 3) = 6

Reorder the terms:
-4 + 4r + 2(3 + r) = 6
-4 + 4r + (3 * 2 + r * 2) = 6
-4 + 4r + (6 + 2r) = 6

Reorder the terms:
-4 + 6 + 4r + 2r = 6

Combine like terms: -4 + 6 = 2
2 + 4r + 2r = 6

Combine like terms: 4r + 2r = 6r
2 + 6r = 6

Solving
2 + 6r = 6

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6r = 6 + -2

Combine like terms: 2 + -2 = 0
0 + 6r = 6 + -2
6r = 6 + -2

Combine like terms: 6 + -2 = 4
6r = 4

Divide each side by '6'.
r = 0.6666666667

Simplifying
r = 0.6666666667

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