4(r-1)+2(r-3)=6

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Solution for 4(r-1)+2(r-3)=6 equation: 



4(r-1)+2(r-3)=6

We move all terms to the left:

4(r-1)+2(r-3)-(6)=0

We multiply parentheses

4r+2r-4-6-6=0

We add all the numbers together, and all the variables

6r-16=0

We move all terms containing r to the left, all other terms to the right

6r=16

r=16/6

r=2+2/3

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