4(r-1)+3(6r+2)=13

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Solution for 4(r-1)+3(6r+2)=13 equation: 



4(r-1)+3(6r+2)=13

We move all terms to the left:

4(r-1)+3(6r+2)-(13)=0

We multiply parentheses

4r+18r-4+6-13=0

We add all the numbers together, and all the variables

22r-11=0

We move all terms containing r to the left, all other terms to the right

22r=11

r=11/22

r=1/2

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