4(r-2)=5-(r-2)

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Solution for 4(r-2)=5-(r-2) equation: 



4(r-2)=5-(r-2)

We move all terms to the left:

4(r-2)-(5-(r-2))=0

We multiply parentheses

4r-(5-(r-2))-8=0



We calculate terms in parentheses: -(5-(r-2)), so:

5-(r-2)

determiningTheFunctionDomain
-(r-2)+5

We get rid of parentheses

-r+2+5

We add all the numbers together, and all the variables

-1r+7

Back to the equation:

-(-1r+7)



We get rid of parentheses

4r+1r-7-8=0

We add all the numbers together, and all the variables

5r-15=0

We move all terms containing r to the left, all other terms to the right

5r=15

r=15/5

r=3

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