4(r-3)=r+15

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Solution for 4(r-3)=r+15 equation: 



4(r-3)=r+15

We move all terms to the left:

4(r-3)-(r+15)=0

We multiply parentheses

4r-(r+15)-12=0

We get rid of parentheses

4r-r-15-12=0

We add all the numbers together, and all the variables

3r-27=0

We move all terms containing r to the left, all other terms to the right

3r=27

r=27/3

r=9

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