4(r-5)=32-20

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Solution for 4(r-5)=32-20 equation: 



4(r-5)=32-20

We move all terms to the left:

4(r-5)-(32-20)=0

We add all the numbers together, and all the variables

4(r-5)-12=0

We multiply parentheses

4r-20-12=0

We add all the numbers together, and all the variables

4r-32=0

We move all terms containing r to the left, all other terms to the right

4r=32

r=32/4

r=8

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