4(r-6)-3(r-1)=2(r+7)

Solution for 4(r-6)-3(r-1)=2(r+7) equation:

4(r-6)-3(r-1)=2(r+7)

We move all terms to the left:

4(r-6)-3(r-1)-(2(r+7))=0

We multiply parentheses

4r-3r-(2(r+7))-24+3=0


We calculate terms in parentheses: -(2(r+7)), so:

2(r+7)

We multiply parentheses

2r+14

Back to the equation:

-(2r+14)


We add all the numbers together, and all the variables

r-(2r+14)-21=0

We get rid of parentheses

r-2r-14-21=0

We add all the numbers together, and all the variables

-1r-35=0

We move all terms containing r to the left, all other terms to the right

-r=35

r=35/-1

r=-35