4(r-7)+1=5(r+3)-26

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Solution for 4(r-7)+1=5(r+3)-26 equation:


Simplifying
4(r + -7) + 1 = 5(r + 3) + -26

Reorder the terms:
4(-7 + r) + 1 = 5(r + 3) + -26
(-7 * 4 + r * 4) + 1 = 5(r + 3) + -26
(-28 + 4r) + 1 = 5(r + 3) + -26

Reorder the terms:
-28 + 1 + 4r = 5(r + 3) + -26

Combine like terms: -28 + 1 = -27
-27 + 4r = 5(r + 3) + -26

Reorder the terms:
-27 + 4r = 5(3 + r) + -26
-27 + 4r = (3 * 5 + r * 5) + -26
-27 + 4r = (15 + 5r) + -26

Reorder the terms:
-27 + 4r = 15 + -26 + 5r

Combine like terms: 15 + -26 = -11
-27 + 4r = -11 + 5r

Solving
-27 + 4r = -11 + 5r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-5r' to each side of the equation.
-27 + 4r + -5r = -11 + 5r + -5r

Combine like terms: 4r + -5r = -1r
-27 + -1r = -11 + 5r + -5r

Combine like terms: 5r + -5r = 0
-27 + -1r = -11 + 0
-27 + -1r = -11

Add '27' to each side of the equation.
-27 + 27 + -1r = -11 + 27

Combine like terms: -27 + 27 = 0
0 + -1r = -11 + 27
-1r = -11 + 27

Combine like terms: -11 + 27 = 16
-1r = 16

Divide each side by '-1'.
r = -16

Simplifying
r = -16

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