4(r-8)+4(r+5)=r-6+8r

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Solution for 4(r-8)+4(r+5)=r-6+8r equation: 



4(r-8)+4(r+5)=r-6+8r

We move all terms to the left:

4(r-8)+4(r+5)-(r-6+8r)=0

We add all the numbers together, and all the variables

4(r-8)+4(r+5)-(9r-6)=0

We multiply parentheses

4r+4r-(9r-6)-32+20=0

We get rid of parentheses

4r+4r-9r+6-32+20=0

We add all the numbers together, and all the variables

-1r-6=0

We move all terms containing r to the left, all other terms to the right

-r=6

r=6/-1

r=-6

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