4(s+1)+2(s+3)=

Solution for 4(s+1)+2(s+3)= equation:

Simplifying
4(s + 1) + 2(s + 3) = 0

Reorder the terms:
4(1 + s) + 2(s + 3) = 0
(1 * 4 + s * 4) + 2(s + 3) = 0
(4 + 4s) + 2(s + 3) = 0

Reorder the terms:
4 + 4s + 2(3 + s) = 0
4 + 4s + (3 * 2 + s * 2) = 0
4 + 4s + (6 + 2s) = 0

Reorder the terms:
4 + 6 + 4s + 2s = 0

Combine like terms: 4 + 6 = 10
10 + 4s + 2s = 0

Combine like terms: 4s + 2s = 6s
10 + 6s = 0

Solving
10 + 6s = 0

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 6s = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 6s = 0 + -10
6s = 0 + -10

Combine like terms: 0 + -10 = -10
6s = -10

Divide each side by '6'.
s = -1.666666667

Simplifying
s = -1.666666667