4(s+1)=12(s+3)

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Solution for 4(s+1)=12(s+3) equation:


Simplifying
4(s + 1) = 12(s + 3)

Reorder the terms:
4(1 + s) = 12(s + 3)
(1 * 4 + s * 4) = 12(s + 3)
(4 + 4s) = 12(s + 3)

Reorder the terms:
4 + 4s = 12(3 + s)
4 + 4s = (3 * 12 + s * 12)
4 + 4s = (36 + 12s)

Solving
4 + 4s = 36 + 12s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-12s' to each side of the equation.
4 + 4s + -12s = 36 + 12s + -12s

Combine like terms: 4s + -12s = -8s
4 + -8s = 36 + 12s + -12s

Combine like terms: 12s + -12s = 0
4 + -8s = 36 + 0
4 + -8s = 36

Add '-4' to each side of the equation.
4 + -4 + -8s = 36 + -4

Combine like terms: 4 + -4 = 0
0 + -8s = 36 + -4
-8s = 36 + -4

Combine like terms: 36 + -4 = 32
-8s = 32

Divide each side by '-8'.
s = -4

Simplifying
s = -4

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